# WAP in C to Send all the negative elements of an array to the end without altering the original sequence

The Program in C to Send all the negative elements of an array to the end without altering the original sequence is given below:

``````#include <stdio.h>

void moveNegatives(int array[], int size) {
int i = 0, j = size - 1;

while (i < j) {
if (array[i] < 0) {
if (array[j] >= 0) {
// swap array[i] and array[j]
int temp = array[i];
array[i] = array[j];
array[j] = temp;
i++;
j--;
} else {
j--;
}
} else {
i++;
}
}
}

int main() {
int array[100], size;
printf("Enter the size of array : ");
scanf("%d", &size);
printf("Enter the elements of array : ");
for (int i = 0; i < size; i++) {
scanf("%d", &array[i]);
}

moveNegatives(array, size);

printf("After moving negatives to end : ");
for (int i = 0; i < size; i++) {
printf("%d ", array[i]);
}

return 0;
}
``````

## Output:

Enter the size of array : 4
Enter the elements of array : -1
2
-7
5
After moving negatives to end : 5 2 -7 -1

## Pro-Tips💡

This program takes input from the user for the array and its size, and then calls the “moveNegatives” function which uses a two-pointer approach to move all negative elements to the end of the array.

It starts with two pointers i and j, one pointing to the first element and another to the last element, then it iterates over the array, and if the element at i is negative and the element at j is non-negative, it swaps the elements and increments i and decrements j.

If the element at i is non-negative or the element at j is negative, it only increments i or decrements j respectively.

Please note that this code is given as an example and may not be the most efficient or optimal solution for the problem, and also arrays are fixed size in C and if size of array is not sufficient it will cause buffer overflow.

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