**The Program in C that will read 2 matrices, multiply the matrices and display the resultant matrix is given below**:

```
#include <stdio.h>
int main() {
int m1, n1, m2, n2;
printf("Enter the number of rows and columns of the first matrix: ");
scanf("%d %d", &m1, &n1);
printf("Enter the number of rows and columns of the second matrix: ");
scanf("%d %d", &m2, &n2);
if (n1 != m2) {
printf("Error: The number of columns of the first matrix must be equal to the number of rows of the second matrix.\n");
return 1;
}
int matrix1[m1][n1], matrix2[m2][n2], result[m1][n2];
printf("Enter the elements of the first matrix: \n");
for (int i = 0; i < m1; i++) {
for (int j = 0; j < n1; j++) {
scanf("%d", &matrix1[i][j]);
}
}
printf("Enter the elements of the second matrix: \n");
for (int i = 0; i < m2; i++) {
for (int j = 0; j < n2; j++) {
scanf("%d", &matrix2[i][j]);
}
}
for (int i = 0; i < m1; i++) {
for (int j = 0; j < n2; j++) {
result[i][j] = 0;
for (int k = 0; k < n1; k++) {
result[i][j] += matrix1[i][k] * matrix2[k][j];
}
}
}
printf("The result of multiplying the two matrices is: \n");
for (int i = 0; i < m1; i++) {
for (int j = 0; j < n2; j++) {
printf("%d ", result[i][j]);
}
printf("\n");
}
return 0;
}
```

## Output:

Enter the number of rows and columns of the first matrix: 1

1

Enter the number of rows and columns of the second matrix: 1

1

Enter the elements of the first matrix:

34

Enter the elements of the second matrix:

43

The result of multiplying the two matrices is:

1462

## Pro-Tips**💡**

This program prompts the user to enter the number of rows and columns of two matrices, and then the elements of each matrix.

It then checks if the number of columns of the first matrix is equal to the number of rows of the second matrix, which is a necessary condition for matrix multiplication.

If the matrices cannot be multiplied, the program will print an error message and exit.

If the matrices can be multiplied, the program will use the matrix multiplication formula to compute the product of the two matrices and store the result in a new matrix.

The result matrix is displayed element by element, with each row on a new line.

**Learn C-Sharp ↗**

C-sharp covers every topic to learn about C-Sharp thoroughly.

**Learn C Programming ↗**

C-Programming covers every topic to learn about C-Sharp thoroughly.

**Learn C++ Programming↗**

**Learn C++ Programming↗**

C++ covers every topic to learn about C-Sharp thoroughly.