**The Program in C to print all those elements of a matrix are not diagonal elements is given below**

```
#include <stdio.h>
void print_non_diagonal(int *matrix, int rows, int cols) {
for (int i = 0; i < rows; i++) {
for (int j = 0; j < cols; j++) {
if (i != j) {
printf("%d ", matrix[i*cols + j]);
}
}
}
}
int main() {
int rows, cols, i, j;
printf("Enter the number of rows: ");
scanf("%d", &rows);
printf("Enter the number of columns: ");
scanf("%d", &cols);
int matrix[rows][cols];
printf("Enter the elements of the matrix: \n");
for (i = 0; i < rows; i++) {
for (j = 0; j < cols; j++) {
scanf("%d", &matrix[i][j]);
}
}
printf("Non-diagonal elements of the matrix: \n");
print_non_diagonal((int*)matrix, rows, cols);
return 0;
}
```

## Output:

Enter the number of rows: 2

Enter the number of columns: 2

Enter the elements of the matrix:

67

88

99

13

Non-diagonal elements of the matrix:

88 99

## Pro-Tips**💡**

This program prompts the user to enter the number of rows and columns of the matrix, and then the elements of the matrix.

It then uses the function print_non_diagonal which uses nested loops to iterate through the elements of the matrix and it checks if the current element is not on the diagonal (i.e, i is not equal to j) and if it’s true then it prints the element.

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