**The Program in C to print 1-X2 /Y + X4/Y3 -…..N is given belo**w:

```
#include <stdio.h>
#include <math.h>
int main() {
int n;
double x, y, sum = 0;
printf("Enter the value of x: ");
scanf("%lf", &x);
printf("Enter the value of y: ");
scanf("%lf", &y);
printf("Enter the value of n: ");
scanf("%d", &n);
for (int i = 0; i <= n; i += 2) {
sum += pow(-1, i/2) * pow(x, i) / pow(y, i + 1);
}
printf("The sum of the series is: %lf", sum);
return 0;
}
```

## Output:

Enter the value of x: 3

Enter the value of y: 5

Enter the value of n: 7

The sum of the series is: 0.144589

## Pro-Tips**💡**

This program prompts the user to enter the value of x, y and n and then calculates the sum of the series using a for loop.

The for loop iterates from 0 to n by 2 increments and for each iteration, the program raises x to the power of i and y to the power of (i+1) ,

then it multiply the result of (x^i/y^(i+1)) by (-1)^(i/2) and adds it to the sum and prints the final result.

The program uses the `pow`

function from the `math.h`

library to raise numbers to a power.

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