The Program in C to Develop mini calculator Using switch with Case is given below:
#include <stdio.h>
int main() {
char operator;
double num1, num2, result;
printf("Enter an operator (+, -, *, /): ");
scanf("%c", &operator);
printf("Enter two operands: ");
scanf("%lf %lf", &num1, &num2);
switch(operator) {
case '+':
result = num1 + num2;
printf("%.1lf + %.1lf = %.1lf\n", num1, num2, result);
break;
case '-':
result = num1 - num2;
printf("%.1lf - %.1lf = %.1lf\n", num1, num2, result);
break;
case '*':
result = num1 * num2;
printf("%.1lf * %.1lf = %.1lf\n", num1, num2, result);
break;
case '/':
if(num2 == 0) {
printf("Error: Cannot divide by zero!\n");
} else {
result = num1 / num2;
printf("%.1lf / %.1lf = %.1lf\n", num1, num2, result);
}
break;
default:
printf("Error: Invalid operator!\n");
}
return 0;
}
Output:
Enter an operator (+, -, *, /): +
Enter two operands: 56
100
56.0 + 100.0 = 156.0
Pro-Tips💡
This program prompts the user to enter an operator (+, -, *, /) and two operands (numbers).
Then, it uses a switch statement to perform the appropriate calculation based on the operator entered by the user. The program will print the result of the calculation with the operands and operator.
If the operator is not one of the four supported operator or if the user tries to divide by zero, it will print an error message.
You can also add more functionality like modulus, power, square root and more operators.
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