The Program in C++ to Test the Type Casting is given below:

#include <iostream>

int main() {
    int a;
    double b;

    std::cout << "Enter an integer: ";
    std::cin >> a;

    std::cout << "Enter a double: ";
    std::cin >> b;

    // Implicit type casting
    double c = a + b; // a is implicitly cast to double
    std::cout << "Implicit type casting: " << c << std::endl;

    // Explicit type casting
    int d = (int)(a + b); // a + b is explicitly cast to int
    std::cout << "Explicit type casting: " << d << std::endl;

    return 0;
}

Output:

Enter an integer: 56
Enter a double: 12
Implicit type casting: 168
Explicit type casting: 168

Pro-Tips💡

This code uses the cin function to read input from the user and store it in the variables a and b.

Then, the code performs the same type casting operations as the previous example, but using the user-provided values for a and b.

The first operation demonstrates implicit type casting, which is when the compiler automatically converts one data type to another without the programmer explicitly requesting the conversion.

In this case, the value of a is implicitly cast to a double when it is added to the value of b, and the result is stored in the variable c.

The second operation demonstrates explicit type casting, which is when the programmer explicitly requests a conversion using the (type) notation.

In this case, the result of the expression a + b is explicitly cast to an int and stored in the variable d.

As the output, it will show the results of the Implicit type casting and the Explicit type casting.

It’s important to note that casting can cause data loss if the target data type is not able to represent the value of the original data type.