# C++ Program to Generate Sequence of Primes by means of trial division

The Program in C++ Program to Generate Sequence of Primes by means of trial division is given below:

``````#include <iostream>
#include <cmath>
using namespace std;

bool is_prime(int n) {
if (n <= 1) return false;
for (int i = 2; i <= sqrt(n); i++) {
if (n % i == 0) return false;
}
return true;
}

int main() {
int n;
cout << "Hello Codeauri Family,enter a number here to find out the prime numbers : ";
cin >> n;
cout << "Okay, the prime numbers up to " << n << " are:" << endl;
for (int i = 2; i <= n; i++) {
if (is_prime(i)) cout << i << " ";
}
return 0;
}
``````

## Output:

Hello Codeauri Family,enter a number here to find out the prime numbers : 500
Okay, the prime numbers up to 500 are:
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79 83 89 97 101 103 107 109 113 127 131 137 139 149 151 157 163 167 173 179 181 191 193 197 199 211 223 227 229 233 239 241 251 257 263 269 271 277 281 283 293 307 311 313 317 331 337 347 349 353 359 367 373 379 383 389 397 401 409 419 421 431 433 439 443 449 457 461 463 467 479 487 491 499

## Pro-Tips💡

The `is_prime` function takes an integer `n` as an input and returns a boolean value indicating whether `n` is prime or not.

It first checks if `n` is less than or equal to 1, in which case it returns `false`.

Then, it iterates over numbers from 2 to the square root of `n`, checking if `n` is divisible by the current number.

If it is, the function returns `false` because `n` is not prime. If none of the numbers divide `n`, the function returns `true`, meaning `n` is prime.

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