# C++ Program to Find Perfect numbers between Two Given Numbers

The Program in C++ Program to Find Perfect numbers between Two Given Numbers is given below:

``````#include <iostream>
using namespace std;

bool isPerfect(int num) {
int i, sum = 0;
for (i = 1; i <= num/2; i++) {
if (num % i == 0) {
sum += i;
}
}
return (sum == num);
}

int main() {
int start, end, i;
cout<<"Hello Codeauri Family, enter the two numbers here to find the perfect numbers between them;\n";
cout << "Enter start of range: ";
cin >> start;
cout << "Enter end of range: ";
cin >> end;

cout << "Okay, the Perfect numbers between " << start << " and " << end << " are: " << endl;
for (i = start; i <= end; i++) {
if (isPerfect(i)) {
cout << i << endl;
}
}

return 0;
}
``````

## Output:

Hello Codeauri Family, enter the two numbers here to find the perfect numbers between them;
Enter start of range: 1
Enter end of range: 1000
Okay, the Perfect numbers between 1 and 1000 are:
6
28
496

## Pro-Tips💡

In this program, we first define a helper function `isPerfect` which takes an integer `num` as input and returns `true` if `num` is a perfect number and `false` otherwise.

The `isPerfect` function uses the same logic as in the previous program to find the sum of the divisors of `num` and compare it with `num`.

The `main` function prompts the user to enter the start and end of the range, and then uses a for loop to iterate through the range,

checking if each number is a perfect number by calling the `isPerfect` function. If a number is a perfect number, it is printed to the screen.

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