The program in C++ to Display n terms of harmonic series and their Sum is given below:
#include <iostream>
using namespace std;
int main() {
int n;
double sum = 0.0;
cout<< "Hello Codeauri Family, enter the value of n to find the harmonic series: \n";
cin >>n;
cout << "The first " << n << " terms of the harmonic series are: ";
for (int i = 1; i <= n; i++) {
cout << "1/" << i << " + ";
sum += 1.0 / i;
}
cout << endl;
cout << "Well,the Sum of the first " << n << " terms of the harmonic series is: " << sum << endl;
return 0;
}
Output:
Hello Codeauri Family, enter the value of n to find the harmonic series:
9
The first 9 terms of the harmonic series are: 1/1 + 1/2 + 1/3 + 1/4 + 1/5 + 1/6 + 1/7 + 1/8 + 1/9 +
Well,the Sum of the first 9 terms of the harmonic series is: 2.82897
Pro-Tips💡
This program prompts the user to enter an integer value for n
, and then uses a for loop to print out the first n
terms of the harmonic series and calculate their sum.
The sum is then displayed at the end.
Since the harmonic series sum converges to log(n) , it’s a good practice to use floating point variable instead of integers.
Note that this program uses standard input/output library <iostream>
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