The Program in C++ Program to Check Whether a given number is Perfect or not is given below:
#include <iostream>
using namespace std;
int main() {
int num, i, sum = 0;
cout << "Hello Codeauri Family,enter a Perfect Number here: ";
cin >> num;
for (i = 1; i <= num/2; i++) {
if (num % i == 0) {
sum += i;
}
}
if (sum == num) {
cout << num << " is a perfect number." << endl;
} else {
cout << num << " is not a perfect number." << endl;
}
return 0;
}
Output:
Hello Codeauri Family,enter a Perfect Number here: 28
28 is a perfect number.
Pro-Tips💡
The main function is the entry point of the program.
Here we declare three variables: num to store the user’s input, i to use as a loop variable, and sum to store the sum of the divisors of num.
We then prompt the user to enter a positive integer and store it in num
This for loop runs i from 1 to num/2, checking if i is a divisor of num by using the modulus operator %. If i is a divisor of num, we add it to sum.
Finally, after the loop, we check if sum is equal to num. If it is, num is a perfect number and we print a message saying so.
If sum is not equal to num, num is not a perfect number and we print a message saying so.
The return 0; statement at the end of the main function returns 0 to indicate that the program has executed successfully.
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