C++ Examples

C++ Program to Check If Given number is Abundant or not

The Program in C++ Program to Check If Given number is Abundant or not is given below:

#include <iostream>

// Function to find the sum of proper divisors of a number
int sumOfProperDivisors(int num) {
  int sum = 0;
  for (int i = 1; i < num; i++) {
    if (num % i == 0) sum += i;
  }
  return sum;
}

// Function to check if a number is abundant
bool isAbundant(int num) {
  return sumOfProperDivisors(num) > num;
}

int main() {
  int num;
  std::cout << "Hello Codeauri Family,enter a number here to check whether the number is ugly or not!\n";
  std::cin >> num;
  
  // Check if the number is abundant
  if (isAbundant(num)) {
    std::cout << num << " is an abundant number." << std::endl;
  } else {
    std::cout << num << " is not an abundant number." << std::endl;
  }
  
  return 0;
}

Output:

Hello Codeauri Family,enter a number here to check whether the number is ugly or not!
12
12 is an abundant number.

Pro-Tips💡

An abundant number is a number for which the sum of its proper divisors (the divisors excluding the number itself) is greater than the number itself.

The sumOfProperDivisors function takes a number as input and returns the sum of its proper divisors.

The isAbundant function takes a number as input and returns true if it is an abundant number and false otherwise.

The function uses the sumOfProperDivisors function to calculate the sum of the proper divisors of the number and returns true if the sum is greater than the number, and false otherwise.

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