# C++ Program to check whether a number is a Strong Number or not

The Program in C++ Program to check whether a number is a Strong Number or not is given below:

``````#include <iostream>
#include <cmath>

using namespace std;

int factorial(int n) {
int result = 1;
for (int i = 1; i <= n; i++) {
result *= i;
}
return result;
}

int sum_of_factorials(int n) {
int sum = 0;
while (n != 0) {
int digit = n % 10;
sum += factorial(digit);
n /= 10;
}
return sum;
}

bool is_Strong(int n) {
return n == sum_of_factorials(n);
}

int main() {
int n;
cout << "Hello Codeauri Family,Enter a number here to check whether the number is strong number or not!: \n";
cin >> n;
if (is_Strong(n)) {
cout << n << " is a Strong Number" << endl;
} else {
cout << n << " is not a Strong Number" << endl;
}
return 0;
}
``````

## Output:

Hello Codeauri Family,Enter a number here to check whether the number is strong number or not!:
145
145 is a Strong Number

## Pro-Tips💡

The program defines two functions, `factorial` and `sum_of_factorials`.

The `factorial` function takes an integer `n` as input and returns its factorial.

The `sum_of_factorials` function takes an integer `n` as input and returns the sum of the factorials of its digits.

The `is_Strong` function takes an integer `n` as input and returns a Boolean indicating whether `n` is a Strong number or not.

It does this by calling the `sum_of_factorials` function with `n` as input and comparing the result with `n`.

In the `main` function, the program prompts the user to enter a number and stores the input in the `n` variable.

Then it calls the `is_Strong` function with `n` as input and prints whether `n` is a Strong number or not based on the result.

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