# C++ Program to Check if two numbers are Amicable numbers or not

The Program in C++ Program to Check if two numbers are Amicable numbers or not is given below:

``````#include <iostream>
#include <cmath>

using namespace std;

int sumOfDivisors(int n) {
int sum = 0;
for (int i = 1; i <= sqrt(n); i++) {
if (n % i == 0) {
if (i == (n / i)) {
sum += i;
} else {
sum += i + n / i;
}
}
}
return sum - n;
}

bool areAmicableNumbers(int a, int b) {
return sumOfDivisors(a) == b && sumOfDivisors(b) == a;
}

int main() {
int a, b;
cout << "Hello Codeauri Family,Enter two numbers here if it is amicable number or not!:\n ";
cin >> a >> b;
if (areAmicableNumbers(a, b)) {
cout << a << " and " << b << " are Amicable Numbers." << endl;
} else {
cout << a << " and " << b << " are not Amicable Numbers." << endl;
}
return 0;
}
``````

## Output:

Hello Codeauri Family,Enter two numbers here if it is amicable number or not!:
220
284
220 and 284 are Amicable Numbers.

## Pro-Tips💡

This program implements a function `sumOfDivisors` to calculate the sum of divisors of a number.

The function loops through all numbers less than or equal to the square root of `n` and checks if `n` is divisible by the number.

If `n` is divisible by the number, the number and `n` divided by the number are added to the sum of divisors. The function returns the sum of divisors minus `n` because `n` is not a divisor of itself.

The `areAmicableNumbers` function uses the `sumOfDivisors` function to calculate the sum of divisors of `a` and `b`,

then returns true if the sum of divisors of `a` is equal to `b` and the sum of divisors of `b` is equal to `a`, indicating that `a` and `b` are Amicable Numbers.

The `main` function prompts the user to enter two numbers and calls the `areAmicableNumbers` function with the inputs.

If the function returns true, the numbers are Amicable Numbers and the program prints a message to that effect.

If the function returns false, the numbers are not Amicable Numbers and the program prints a message to that effect.

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