**The Program in C++ Program to Check if two numbers are Amicable numbers or not is given below:**

```
#include <iostream>
#include <cmath>
using namespace std;
int sumOfDivisors(int n) {
int sum = 0;
for (int i = 1; i <= sqrt(n); i++) {
if (n % i == 0) {
if (i == (n / i)) {
sum += i;
} else {
sum += i + n / i;
}
}
}
return sum - n;
}
bool areAmicableNumbers(int a, int b) {
return sumOfDivisors(a) == b && sumOfDivisors(b) == a;
}
int main() {
int a, b;
cout << "Hello Codeauri Family,Enter two numbers here if it is amicable number or not!:\n ";
cin >> a >> b;
if (areAmicableNumbers(a, b)) {
cout << a << " and " << b << " are Amicable Numbers." << endl;
} else {
cout << a << " and " << b << " are not Amicable Numbers." << endl;
}
return 0;
}
```

## Output:

Hello Codeauri Family,Enter two numbers here if it is amicable number or not!:

220

284

220 and 284 are Amicable Numbers.

## Pro-Tips**💡**

This program implements a function `sumOfDivisors`

to calculate the sum of divisors of a number.

The function loops through all numbers less than or equal to the square root of `n`

and checks if `n`

is divisible by the number.

If `n`

is divisible by the number, the number and `n`

divided by the number are added to the sum of divisors. The function returns the sum of divisors minus `n`

because `n`

is not a divisor of itself.

The `areAmicableNumbers`

function uses the `sumOfDivisors`

function to calculate the sum of divisors of `a`

and `b`

,

then returns true if the sum of divisors of `a`

is equal to `b`

and the sum of divisors of `b`

is equal to `a`

, indicating that `a`

and `b`

are Amicable Numbers.

The `main`

function prompts the user to enter two numbers and calls the `areAmicableNumbers`

function with the inputs.

If the function returns true, the numbers are Amicable Numbers and the program prints a message to that effect.

If the function returns false, the numbers are not Amicable Numbers and the program prints a message to that effect.

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